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- import { isTag, hasChildren } from "domhandler";
- /**
- * Search a node and its children for nodes passing a test function. If `node` is not an array, it will be wrapped in one.
- *
- * @category Querying
- * @param test Function to test nodes on.
- * @param node Node to search. Will be included in the result set if it matches.
- * @param recurse Also consider child nodes.
- * @param limit Maximum number of nodes to return.
- * @returns All nodes passing `test`.
- */
- export function filter(test, node, recurse = true, limit = Infinity) {
- return find(test, Array.isArray(node) ? node : [node], recurse, limit);
- }
- /**
- * Search an array of nodes and their children for nodes passing a test function.
- *
- * @category Querying
- * @param test Function to test nodes on.
- * @param nodes Array of nodes to search.
- * @param recurse Also consider child nodes.
- * @param limit Maximum number of nodes to return.
- * @returns All nodes passing `test`.
- */
- export function find(test, nodes, recurse, limit) {
- const result = [];
- /** Stack of the arrays we are looking at. */
- const nodeStack = [nodes];
- /** Stack of the indices within the arrays. */
- const indexStack = [0];
- for (;;) {
- // First, check if the current array has any more elements to look at.
- if (indexStack[0] >= nodeStack[0].length) {
- // If we have no more arrays to look at, we are done.
- if (indexStack.length === 1) {
- return result;
- }
- // Otherwise, remove the current array from the stack.
- nodeStack.shift();
- indexStack.shift();
- // Loop back to the start to continue with the next array.
- continue;
- }
- const elem = nodeStack[0][indexStack[0]++];
- if (test(elem)) {
- result.push(elem);
- if (--limit <= 0)
- return result;
- }
- if (recurse && hasChildren(elem) && elem.children.length > 0) {
- /*
- * Add the children to the stack. We are depth-first, so this is
- * the next array we look at.
- */
- indexStack.unshift(0);
- nodeStack.unshift(elem.children);
- }
- }
- }
- /**
- * Finds the first element inside of an array that matches a test function. This is an alias for `Array.prototype.find`.
- *
- * @category Querying
- * @param test Function to test nodes on.
- * @param nodes Array of nodes to search.
- * @returns The first node in the array that passes `test`.
- * @deprecated Use `Array.prototype.find` directly.
- */
- export function findOneChild(test, nodes) {
- return nodes.find(test);
- }
- /**
- * Finds one element in a tree that passes a test.
- *
- * @category Querying
- * @param test Function to test nodes on.
- * @param nodes Node or array of nodes to search.
- * @param recurse Also consider child nodes.
- * @returns The first node that passes `test`.
- */
- export function findOne(test, nodes, recurse = true) {
- let elem = null;
- for (let i = 0; i < nodes.length && !elem; i++) {
- const node = nodes[i];
- if (!isTag(node)) {
- continue;
- }
- else if (test(node)) {
- elem = node;
- }
- else if (recurse && node.children.length > 0) {
- elem = findOne(test, node.children, true);
- }
- }
- return elem;
- }
- /**
- * Checks if a tree of nodes contains at least one node passing a test.
- *
- * @category Querying
- * @param test Function to test nodes on.
- * @param nodes Array of nodes to search.
- * @returns Whether a tree of nodes contains at least one node passing the test.
- */
- export function existsOne(test, nodes) {
- return nodes.some((checked) => isTag(checked) &&
- (test(checked) || existsOne(test, checked.children)));
- }
- /**
- * Search an array of nodes and their children for elements passing a test function.
- *
- * Same as `find`, but limited to elements and with less options, leading to reduced complexity.
- *
- * @category Querying
- * @param test Function to test nodes on.
- * @param nodes Array of nodes to search.
- * @returns All nodes passing `test`.
- */
- export function findAll(test, nodes) {
- const result = [];
- const nodeStack = [nodes];
- const indexStack = [0];
- for (;;) {
- if (indexStack[0] >= nodeStack[0].length) {
- if (nodeStack.length === 1) {
- return result;
- }
- // Otherwise, remove the current array from the stack.
- nodeStack.shift();
- indexStack.shift();
- // Loop back to the start to continue with the next array.
- continue;
- }
- const elem = nodeStack[0][indexStack[0]++];
- if (!isTag(elem))
- continue;
- if (test(elem))
- result.push(elem);
- if (elem.children.length > 0) {
- indexStack.unshift(0);
- nodeStack.unshift(elem.children);
- }
- }
- }
- //# sourceMappingURL=querying.js.map
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